DEmotivationals

[Pat]

WIIIIIIIIIIIIIITCHCRAFT!!!

[NotoriousM4^]

[EpicPhailure]

There was a funnier version of this, but I can't seem to find a fullsized version of it.

[NotoriousM4^]

[DarkBlade325]

[Chaos]

There was a funnier version of this, but I can't seem to find a fullsized version of it.

So the real question is...who here besides myself knows enough about math to explain why that doesn't actually work? ;)

[Lucifer]

Not I!

[God-I-Suck]

We don't know what a or b is..

[Mr Pwnage]

We don't know what a or b is..

That's what they teach you in algebra...lol. Yes, it is pretty obvious why that doesn't work...but I won't spoil it just yet. ;)

And here...

[God-I-Suck]

I have the best algebra teacher in the district, that was from my own perspective, besides, it says (a+b) = b, and that's impossible. Unless a and b is 0.

[Torch]

There was a funnier version of this, but I can't seem to find a fullsized version of it.

So the real question is...who here besides myself knows enough about math to explain why that doesn't actually work? ;)

The transition between (a+b) = b and a +a = a doesn't make sense because we don't know that a and b have the same value.

[Mr Pwnage]

There was a funnier version of this, but I can't seem to find a fullsized version of it.

So the real question is...who here besides myself knows enough about math to explain why that doesn't actually work? ;)

The transition between (a+b) = b and a +a = a doesn't make sense because we don't know that a and b have the same value.

Wrong. We do know they have the same value because it says so in the first line: "a = b"
and actually it is perfectly correct up until the very end. Assuming both A and B are 0, let me show you:

0=0

0^2=0(0)
0=0

0^2-0^2=0(0)-0^2
0=0

(0+0)(0-0)=0(0-0)
0=0

(0+0)=0    ------------> Also on this line is where a=2 and b=2 becomes impossible: ( (2+2)=2 doesn't work...therefore a and b ALREADY have to be 0 )

0+0=0

2(0)=0

0=0


THEREFORE:
a=0
b=0

[BraveBro2]

There was a funnier version of this, but I can't seem to find a fullsized version of it.

Well, the real problem is the second line.  You cannot arbitrarily multiply the equation by a.  If you were going to multiply the equation by anything with a, you'd have to multiply by 1 (a/a).  You can't just pull a number out of your ass and multiply the equation by it because you feel like it.

[Trogdor]

Well, the real problem is the second line.  You cannot arbitrarily multiply the equation by a.  If you were going to multiply the equation by anything with a, you'd have to multiply by 1 (a/a).  You can't just pull a number out of your ass and multiply the equation by it because you feel like it.

Sure you could, as long as you do the exact same thing to one side as you did with the other. That way the equation would still be true. If I had the equation 4 = 4 for example, I could multiply both sides by, say, a smiley face :). That way I'd get 4(:)) = 4(:)), and the equation would still hold to be true.

[EpicPhailure]

Well, the real problem is the second line.  You cannot arbitrarily multiply the equation by a.  If you were going to multiply the equation by anything with a, you'd have to multiply by 1 (a/a).  You can't just pull a number out of your ass and multiply the equation by it because you feel like it.

Sure you could, as long as you do the exact same thing to one side as you did with the other. That way the equation would still be true. If I had the equation 4 = 4 for example, I could multiply both sides by, say, a smiley face :). That way I'd get 4(:)) = 4(:)), and the equation would still hold to be true.

It works through the Addition Property of Equality.

I believe the problem here is in the 4th line down, where (a+b)(a-b) = b(a-b).